I need help with a chemistry question

[Rich Duncan]

More specifically, Calorimetry. I am pretty bad at it and need help with this question:

In an experiment, 400. mL of 0.600 M HNO3(aq) is mixed with 400. mL of 0.300 M Ba(OH)2(aq) in a constant-pressure calorimeter having a heat capacity of 387 J/oC. The initial temperature of both solutions is the same at 18.88oC, and the final temperature of the mixed solution is 22.49oC. Calculate the heat of neutralization in kJ per mole of HNO3.

If anyone could help me set it up, I would be very appreciative.

[Alan Rupp]

Where are richter and Tony? They're chemistry pros.

Well, because I have a feeling this is due tomorrow, I'll give it a shot based on the very very little thermo and chem I remember from two years ago.

My best guess:

Of course, heat of neutralization means delta-H.

delta-H is defined as C*delta-T.

C*delta-T is 0.387 kJ/oC * (22.49oC - 18.88oC) = 1.397 kJ

delta-H is most likely delta-H-bar (change in enthalpy per mole) and you have 0.24 mol HNO3 (aq).

I have no idea where I'm going with that, but maybe it helped?

Can you look up delta-H values in an index or something and then plug them into the formula?

Good luck man, you're on your own.

[ghostyouare]

omgomgomgogmoomgomgomog are my eyes deceiving me?!?/1/1/!??!? omgomgmo

[aminorthreat55]

omgomgomgogmoomgomgomog are my eyes deceiving me?!?/1/1/!??!? omgomgmo
I just had the same reaction.

[sleepygrlgreen]

Where are richter and Tony? They're chemistry pros.

Well, because I have a feeling this is due tomorrow, I'll give it a shot based on the very very little thermo and chem I remember from two years ago.

My best guess:

Of course, heat of neutralization means delta-H.

delta-H is defined as C*delta-T.

C*delta-T is 0.387 kJ/oC * (22.49oC - 18.88oC) = 1.397 kJ

delta-H is most likely delta-H-bar (change in enthalpy per mole) and you have 0.24 mol HNO3 (aq).

I have no idea where I'm going with that, but maybe it helped?

Can you look up delta-H values in an index or something and then plug them into the formula?

Good luck man, you're on your own.Richter is busy studying for a Physics midterm, which he'll pwn x10.

[richter915]

Richter is busy studying for a Physics midterm, which he'll pwn x10.
actually...shouldn't u be able to answer this considering it's what you guys did on ur first midterm?

the equation alan put up is good but it does get confusing with this whole thing when you talk about different heat values...seeing this equation tempts me to think of q=mc(deltaT)...u can also use moles instead of mass...I think you'd use the moles of ur limiting reagent...