I Need Help With Algebra

[Bd_fallen]

anybody??
pretty please?
im so so bad at math

[Bd_fallen]

:ugo:

[Praetor]

Isolate the variable.

/thread

[Neo Cassady]

Algebra covers a lot of stuff. Narrow that down some.

[Bd_fallen]

pretty much everything but mostly factoring trinomials and stuff like that

[Renee]

trinomials factor into (x+-#)(x+-#)
do you know F.O.I.L?

[stayforawhile]

factoring as in making xsquared+7x+12 into (x+3)(x+4)?

[Bd_fallen]

yeah but FOIL confuses me sometimes
is there an easier way?

[stayforawhile]

well FOIL is for taking the two ()() parts into xsquared+x+1
is that what you need to do or make xsquared+x+1 into ()()

[Bd_fallen]

thank you

[stayforawhile]

which one I'll try to explain it just which one do you have to do?

[Bd_fallen]

well im not on that problem anymore
(im doing my math class online)
when i come across another one i'll put it up here

[idowhatiamtold]

Basic algebra method to follow. (PEMDAS) P - parenthesis E - exponents M - multiply D - Divide A - Add S - Subtract. Know this and practice it.

[Neo Cassady]

Basic algebra method to follow. (PEMDAS) P - parenthesis E - exponents M - multiply D - Divide A - Add S - Subtract. Know this and practice it.

Please Excuse My Dear Aunt Sally

[Bd_fallen]

what about the methods of factoring?
polynomials and stuff??

[brknhrtdbritt]

hun... what you need? what the question?

[Bd_fallen]

hun... what you need? what the question?

you can move in with me if you finish my math for me :biggrin:

[brknhrtdbritt]

you can move in with me if you finish my math for me :biggrin:

HAHA sounds rather tempting but i have 54 lessons and a test i keep scoring 75's on so i have to keep retaking it till i get an 80.... i wish i could take it over but english is draining me out...:skull:

[Neo Cassady]

what about the methods of factoring?
polynomials and stuff??

The absolute easiest way to do it is draw a picture. Say you have x^2 + 6x (since that's what works with the picture I found; I don't really have time to make one). Draw a square with area x^2 (which is an x by x square). Then add a rectangle with area 6x (6 by x) to one side. This makes a rectangle in which each part of said expression is the area of one part of the rectangle (see picture; the areas are x^2 and 6x). Then figure out the dimensions of each rectangle: x^2 is x by x; 6x is x by 6. Then, look at each side as a factor. The factored expression is x(x+6). Think of it like, expanded form is the areas of the rectangles, and factored form is the sides (the sides are the factors).

`http://www.helpalgebra.com/articles/images/csa1.gif

For expressions with an integer at the end (example x^2 + 3x + 9), do the same thing but extend your x^2 square along both axes. The 9 is the extra space in the corner. I can try to explain this more if you need it.


http://www.helpalgebra.com/articles/images/csa3.gif

Sorry if that was confusing; it's hard to explain in writing.

[brknhrtdbritt]

Awe Thnx Jeff!!!

[Neo Cassady]

No problem. I figure I should brush up on my Algebra explainin' skills since there's a good chance I'm going to be teaching it in a year.

[brknhrtdbritt]

No problem. I figure I should brush up on my Algebra explainin' skills since there's a good chance I'm going to be teaching it in a year.

really? thats kinda cool! where you going to be teaching?

[Neo Cassady]

really? thats kinda cool! where you going to be teaching?

Not sure yet. I have to start applying for jobs early next year (I graduate in May). I'll probably stay in Ohio, but it depends on how adventurous I feel when I start sending out resumes.

[brknhrtdbritt]

Not sure yet. I have to start applying for jobs early next year (I graduate in May). I'll probably stay in Ohio, but it depends on how adventurous I feel when I start sending out resumes.

nice!!! i move to idaho in may next year and then in june im going to ohio to stay with a friend for a bit... good luck with the teaching

[Neo Cassady]

nice!!! i move to idaho in may next year and then in june im going to ohio to stay with a friend for a bit... good luck with the teaching

Thanks. Hopefully you're staying in a good part of Ohio haha.

[brknhrtdbritt]

Thanks. Hopefully you're staying in a good part of Ohio haha.

haha honestly i have no idea.... whats a good part of ohio?

[Neo Cassady]

haha honestly i have no idea.... whats a good part of ohio?

The suburbs and rural areas vary a lot, but as far as the actual cities go, not Cleveland.

[brknhrtdbritt]

The suburbs and rural areas vary a lot, but as far as the actual cities go, not Cleveland.

ironicly.... i think thats where she lives
:jawdrop: whats so bad about it?

[Bd_fallen]

The absolute easiest way to do it is draw a picture. Say you have x^2 + 6x (since that's what works with the picture I found; I don't really have time to make one). Draw a square with area x^2 (which is an x by x square). Then add a rectangle with area 6x (6 by x) to one side. This makes a rectangle in which each part of said expression is the area of one part of the rectangle (see picture; the areas are x^2 and 6x). Then figure out the dimensions of each rectangle: x^2 is x by x; 6x is x by 6. Then, look at each side as a factor. The factored expression is x(x+6). Think of it like, expanded form is the areas of the rectangles, and factored form is the sides (the sides are the factors).

`http://www.helpalgebra.com/articles/images/csa1.gif

For expressions with an integer at the end (example x^2 + 3x + 9), do the same thing but extend your x^2 square along both axes. The 9 is the extra space in the corner. I can try to explain this more if you need it.


http://www.helpalgebra.com/articles/images/csa3.gif

Sorry if that was confusing; it's hard to explain in writing.



THANK YOU SO MUCH! this helped alot
you'll be a great teacher

[Neo Cassady]

ironicly.... i think thats where she lives
:jawdrop: whats so bad about it?

Haha I dunno, I haven't really been there much. From what I've seen, I just prefer Columbus and Cincy. Chances are she doesn't live IN Cleveland, though. Some of the 'burbs are quite nice.

[brknhrtdbritt]

Haha I dunno, I haven't really been there much. From what I've seen, I just prefer Columbus and Cincy. Chances are she doesn't live IN Cleveland, though. Some of the 'burbs are quite nice.

alright well pray for me haha

[rob_mylo]

i suck at math so bad

[brknhrtdbritt]

i suck at math so bad

haha and yet your commenting in a "help me with algebra" thread.... nice.. want help too?

[Bd_fallen]

i suck at math so bad


yay me too! lets be friends

[brknhrtdbritt]

yay me too! lets be friends

haha brig.. your funny... i could actually see you sayin that in that lil girl voice haha

[rob_mylo]

haha and yet your commenting in a "help me with algebra" thread.... nice.. want help too?

heh, well i have nothing better to do.
and nah, i don't need help. thanks though! haha, i chose a major with no math whatsoever.

[brknhrtdbritt]

heh, well i have nothing better to do.
and nah, i don't need help. thanks though! haha, i chose a major with no math whatsoever.

haha what major is that?! with no math sounds like my kind of major

[rob_mylo]

haha what major is that?! with no math sounds like my kind of major

psychology :-)

[brknhrtdbritt]

psychology :-)
sounds pretty amazing but i'll stick to what i wanna do ha

[rob_mylo]

sounds pretty amazing but i'll stick to what i wanna do ha

good deal. sounds good

[Bd_fallen]

how do you find the slope intercept of a line??????????!!!

[matty p]

how do you find the slope intercept of a line??????????!!!

off the top of my head (aint done this in a while) you use the formula: y = mx+b

y=y coordinate, x = x coordinate, m = slope of the line (gradient), b = intercept of the line with the y-axis

therefore u rearrange it to: b = y - mx

hope that helps

[jds10912]

how do you find the slope intercept of a line??????????!!!
...there really is no such thing as a line's slope intercept
when describing a line, you have 2 important (but separate) pieces of information: the slope and the intercept(s)
slope is the 'steepness' of the line (rise divided by run, the amount that the dependent variable increases for a given increase of the independent variable)
intercept is where the line crosses an axis

a straight line can be expressed in slope-intercept form which is y=m*x+b
y=y coordinate/dependent variable
m=slope
x=x coordinate/independent variable
b=intercept of y axis

in basic algebra you only need to deal with the y intercept, but all linear equations will also have an x intercept. non-linear equations can have multiple intercepts or no intercepts at all

[Renee]

I just got a B+ on my summer Alg. and Trig course. My notebook is in the car, but if you need more help, I can scan some notes, if I have that topic.

[eHaMpToN]

anybody??
pretty please?
im so so bad at math

i wish algebra would die.

[drewziph]

nope

[Bd_fallen]

i wish algebra would die.

oh god me too

[concernedparent]

this is easy shit. Enjoy it

[pwnership]

Can anyone help with this?

http://img.photobucket.com/albums/v416/scrobot/help.jpg

[stayforawhile]

Can anyone help with this?

http://img.photobucket.com/albums/v416/scrobot/help.jpg
I belive the answer tha is f(x)=3b+10.

[perceptrons]

Make the denominators the same, and then just solve for b.

[TotalCollapse]

Can anyone help with this?

http://img.photobucket.com/albums/v416/scrobot/help.jpg
Multiply out the denominators. (b * 5) and (2 * (b + 5)). So 5b - 2b + 10. f(x) = 3b + 10. Domain is b>0.

[Poe-tryGirl]

Dude, I can't help. I suck myself. I'm taking Hon. Algebra 2 next semester. I'm screwed.

[BrennanHickson]

Please Excuse My Dear Aunt Sally
Please Excuse My Dumb Ass Sister

[xfantabulousx]

Go on iTunes and look for Algebra podcasts. There's a lot of free video podcasts that are almost complete lessons on different topics in math (I've used a couple of the calculus ones and they've helped me out a lot. My teacher is even going to make us watch some of them on snow days so that we don't get behind).