I already know everything.

Originally Posted by Lueda Alia

I already know everything.

Originally Posted by Lueda Alia

I already know everything.

Pretty much.

I really want to see what RepliesWithGIFs comes up with for this one.
Also, cool idea is cool.

Differentiate y=[(lnx)^x]/[2^(3x+1)].

I would like to know if Jason and Zack would play nice and invite the UTG kids to hang. We have daleks. We'll share them

1) Will members ever have the ability to edit the name of their thread after they make it? (ap.net)

2) Can you give us a ballpark date of when the new site will be live? Sorry if that's been posted in a blog update or something already. (also ap.net)

Originally Posted by blimpcityhero11

Differentiate y=[(lnx)^x]/[2^(3x+1)].

This.

Originally Posted by blimpcityhero11

Differentiate y=[(lnx)^x]/[2^(3x+1)].

The geek in me is crying out to give that a go!

Originally Posted by popdisaster00

1) Will members ever have the ability to edit the name of their thread after they make it? (ap.net)

2) Can you give us a ballpark date of when the new site will be live? Sorry if that's been posted in a blog update or something already. (also ap.net)

You can change your username for like $3.

Zack: How does it feel to be bringing along a music website today? How do you think you have it easier or harder than Jason did when he started AP?

Jason, I suppose some version of the above question's converse.

Originally Posted by blimpcityhero11

Differentiate y=[(lnx)^x]/[2^(3x+1)].

2^-3x-1 log^x(x)

Perhaps the best collabo since:

Originally Posted by Jason Tate

2^-3x-1 log^x(x)

I don't know if either that question or answer are real.
Math scares me. It's why I blog.